Pointy from every angle, a hexagonal tube is a three-dimensional object comprised of six flat sides. With its sides shaped like a hexagon, this tube’s length can be inspected by its longest axis. While appearing uniquely designed, this special type of tube actually hails from the more general cylindrical tube family, which typically features a circular cross section.

To determine how much a hexagonal tube can hold, use the equation V = r2h. Here, r stands for the radius of the hexagon (half the size of a single side), while h indicates the height of the tube (length along its foremost axis).

A hexagonal tube with 2-inch sides and 10-inch height is a prime example. Its radius equates to half of the side length so it amounts to 1-inch diameter. In sum, the volume of this tube would be (10 in3), drawn from the equation V = (1 in)2(10 in).

Gauging the quantity of a hexagonal tube is possible with the formula for the volume of a prism- V = Aℓ. This equation involves the area of the hexagon (which can be found with the area of a regular polygon formula) and the length/height of the prism that is the hexagonal tube.

This hexagon has sides of 2 inches in length and 10 inches in height, making its area amount to 3 square inches (A = (3/2)(2 in)2 = 3 in2). When that is multiplied by the height of 10 inches, it amounts to a total volume of 30 cubic inches (V = (3 in2)(10 in) = 30 in3).

To figure out the volume of a hexagonal tube, we can apply the same formula used to compute the volume of a cone: V = (1/3)r2h. Here, r refers to the radius of both the apical base of the cone and the sides of the hexagon, and h corresponds to the cone’s height (its longest dimensional span).

Let’s think about a six-sided tube with sides of two inches in length and ten inches in height. Half of two is one, so the base’s radius is 1 inch. The volume of this tube is V = (1/3)(1 in)2(10 in) = (10/3) in3.